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Simplifying 4c2 + 12c = 16b2 Reorder the terms: 12c + 4c2 = 16b2 Solving 12c + 4c2 = 16b2 Solving for variable 'c'. Reorder the terms: -16b2 + 12c + 4c2 = 16b2 + -16b2 Combine like terms: 16b2 + -16b2 = 0 -16b2 + 12c + 4c2 = 0 Factor out the Greatest Common Factor (GCF), '4'. 4(-4b2 + 3c + c2) = 0 Factor a trinomial. 4((-4b + -1c)(b + -1c)) = 0 Ignore the factor 4.Subproblem 1
Set the factor '(-4b + -1c)' equal to zero and attempt to solve: Simplifying -4b + -1c = 0 Solving -4b + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4b' to each side of the equation. -4b + 4b + -1c = 0 + 4b Combine like terms: -4b + 4b = 0 0 + -1c = 0 + 4b -1c = 0 + 4b Remove the zero: -1c = 4b Divide each side by '-1'. c = -4b Simplifying c = -4bSubproblem 2
Set the factor '(b + -1c)' equal to zero and attempt to solve: Simplifying b + -1c = 0 Solving b + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1b' to each side of the equation. b + -1b + -1c = 0 + -1b Combine like terms: b + -1b = 0 0 + -1c = 0 + -1b -1c = 0 + -1b Remove the zero: -1c = -1b Divide each side by '-1'. c = b Simplifying c = bSolution
c = {-4b, b}
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